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Ok...I'll take a shot at this! (I knew that college physics
course would come in handy one day)
If the truck weighs...say...4000 lbs and the contact patch
on the old tires was 5" wide and 7" long then it was 35 sq inches.
If we assume that the 4000 lbs is equally distributed to each
wheel (well...its not quite equal...but close enough) then the
pressure of the tire on the ground would be 1000/35 or
roughly 28 lbs/sq in. Now if the contact patch for the new
tires is twice as big then that means the pressure is now
1000/70 or roughly 14 lbs/sq in. If the coefficient of friction
is roughly the same, then it seems to me that the bigger
tire would require less effort to turn. I'm assuming that
both the old and new tires were radials.
Ok...I'll quit now. My brain is tired.
Jim M.
Mt Juliet
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